(1) In above equation units of all quantities $\left(C_{P}, C_{V} \text { and } R\right)$ are Joule $m o l^{-1} K^{-1} .$ If $C_{P}$ and $d$ $C_{V}$ are expressed in units calorie $m o l^{-1} K^{-1},$ then $C_{P}-C_{V}=\frac{R}{J}$ Which of the following variables controls the physical properties of a perfect gas (a) pressure (b) temperature (c) volume (d) all of the above (e) atomic mass. How much a) work is done and b) heat is transferred in this process? SHOW SOLUTION (i)$P V=\frac{1}{3} m N c^{2}$ molar gad constant R = 8.3 J mol-1 K-1 (2 Marks) b) The gas is compressed to volume of 0.020 m 3.The temperature of the gas is kept constant. Yes in heating or cooling, a body absorbs or loses energy. A great deal of effort, time, and money has been spent in the quest for the so-called perpetual-motion machine, which is defined as a hypothetical machine that operates or produces useful work indefinitely and/or a hypothetical machine that produces more work or energy than it consumes. Differentiating on both sides, we get, 8. Isobaric, because during heating the temperature of steam does not remain constant. Where $m=$ Mass of one molecule, $N=$ Number of molecules present in volume $V$ and$\bar{c}^{2}=$ Meansquare velocity If $V$ is the volume of $1 g m$ molecule $(1$ mole) of a gas. The increaments in the temperature on kelvin scale are the same as the those of the celsius scale. First law of thermodynamics problem solving. We have transformed classroom in such a way that a student can study anytime anywhere. (d) Now, as internal energy of system depends upon its temperature i.e. (ii) and (iii) Explain the concept of temperature on the basis of kinetic theory? Equal masses of monoatomic gas and diatomic gas at the same temperature are given equal quantities of heat. What are the limitations of first law of thermodynamics ? What do you know about the scientific study? Students may come across some of these questions in the exam. From first law, $\Delta Q=\Delta W+\Delta U$ Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. $\Rightarrow \frac{d P}{d V}=-\frac{P}{V}$ is slope of isothermal curve, Q. Does the mass of body change when it is heated or cooled ? Since glass contracts more than platinum, glass fixes on to the wire. This question bank is designed by expert faculties keeping NCERT in mind and the questions are updated with respect to upcoming Board exams. b) internal energy increases. SHOW SOLUTION No, because internal energy of an ideal gas depends only on temperature of the gas. Accuracy: A team of editors takes feedback from our visitors to keep trivia as up to date and as accurate as possible. Which gas will have greater temperature rise? Q. ... Answer to Question #150491 in Molecular Physics | Thermodynamics for Banda 2020-12-11T00:42:59-0500. $d Q=d U+d W$ The work-done in a cyclic process is equal to the area of the closed curve on a P-V-diagram. Hence, temperature of gas will remain constant. $\left(\frac{d P}{d V}\right)=-\frac{P}{V}$ ………….. (1) What is the range of their speeds? Two bodies at different temperatures $\mathrm{T}_{1}$ and $\mathrm{T}_{2}$if brought in thermal contact do not necessarily settle to the mean temperature $\left(\frac{T_{1}+T_{2}}{2}\right)$. What is the source of mechanical energy so produced ? (i)There is no information about the direction in which change takes place. $\Rightarrow \Delta Q=P \Delta V+\Delta U \quad \Rightarrow C_{P} \Delta T=P \Delta V+\Delta U$ Since, can never be negative, therefore the value of absolute temperature T can never be negative. Q. Due to which the molecules of gas get more space to move about. Although the root mean square speed of gas molecules is of the order of the speed of sound in that gas, yet on opening a bottle of ammonia in one corner of a room its smell takes time in reaching the other corner. Since, can never be negative, therefore the value of absolute temperature. Multiple Choice Questions (MCQ I) Thermodynamics. (b) For an adiabatic process, $P V^{\gamma}=K$ (constant) The LibreTexts libraries are Powered by MindTouch ® and are supported by the Department of Education Open Textbook Pilot Project, the UC Davis Office of the Provost, the UC Davis Library, the California State University Affordable Learning Solutions Program, and Merlot. Answer to Question #150686 in Molecular Physics | Thermodynamics for Danize 2020-12-11T18:57:26-0500. Answer the following Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. SHOW SOLUTION $\left(\frac{d P}{d V}\right)_{A}=\gamma\left(-\frac{P}{V}\right)=\gamma\left(\frac{d P}{d V}\right)_{I}$ Multiple choice questions: 1. (iii)As explained above, there is also no change in temperature. The intermediate states are non-equilibrium states and do not satisfy the gas equation. Part 1 Problem 1. column. What is meant by reversible engine ? $\frac{1}{2} m c^{2}=0$ since $\frac{1}{2} m \neq 0 \quad \therefore c=0$ Further internal energy of an ideal gas depends on temperature only. Total energy associated with a gram molecule of the gas of $\mathrm{Hg}$. $\Delta U=0$. $\Rightarrow \frac{1}{2} M c^{2}=\frac{3}{2} R T$ $\frac{1}{3} M c^{2}=R T$ ……. $(273.16 K)$ at one single pressure of about $0.46 \mathrm{cm}$. 3. This process is achieved Download eSaral App for Video Lectures, Complete Revision, Study Material and much more...Sol. MCQ quiz on Thermodynamics multiple choice questions and answers on Thermodynamics MCQ questions quiz on Thermodynamics objectives questions with answer test pdf. This is the reason due to which the lowest temperature on kelvin’s scale is assumed to be 0K. $\overline{c^{2}} \propto T$ ………(v) We also acknowledge previous National Science Foundation support under grant numbers 1246120, 1525057, and 1413739. (c) has its internal energy changed? $\therefore \frac{d P}{d V}=-\frac{\gamma P V^{\gamma-1}}{V^{\gamma}}=-\frac{\gamma P}{V}$ Physics Important Questions Class 11 are given below. gas: A gas has two specific heats Problem 2. Visit eSaral Website to download or view free study material for JEE & NEET. (ii) What is the change in internal energy of the gas ? Attempt the test, click “ Quiz-summary ” at the same temperature given... For Detailed Notes of heat ( None of the room be cooled has heat been to. Compressing the gas is compressed at constant temperature, and Website in this quiz, you will about. Between $\gamma$ is always steeper than an isothermal process, there no! 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